8.4.xa. Exercise answers

1. a.
using Russell’s analysis:

Sam guessed the winning number

the winning number is such that (Sam guessed it)

(∃x: x is a winning numberonly x is a winning number) Sam guessed x

(∃x: Wx ∧ (∀y: ¬ y = x) ¬ y is a winning number) Gsx

(∃x: Wx ∧ (∀y: ¬ y = x) ¬ Wy) Gsx
∃x (Wx ∧ ∀y (¬ y = x → ¬ Wy) ∧ Gsx)
or:
(∃x: Wx ∧ (∀y: Wy) x = y) Gsx
∃x (Wx ∧ ∀y (Wy → x = y) ∧ Gsx)

G: [ _ guessed _ ]; W: [ _ is a winning number]; s: Sam

Note: [ _ is a winning number] might be open to further analysis as [x is a number ∧ x won]x.

with the description operator:

Sam guessed the winning number

G Sam the winning number

Gs(Ix x is a winning number)

Gs(Ix Wx)

  b.
using Russell’s analysis:

The winner who spoke to Tom was well-known

The winner who spoke to Tom is such that (he or she was well-known)

(∃x: x is a winner who spoke to Tomonly x is a winner who spoke to Tom) x was well-known

(∃x: (x is a winner ∧ x spoke to Tom) ∧ (∀y: ¬ y = x) ¬ (y is a winner ∧ y spoke to Tom)) Kx

(∃x: (Wx ∧ Sxt) ∧ (∀y: ¬ y = x) ¬ (Wy ∧ Syt)) Kx
∃x ((Wx ∧ Sxt) ∧ ∀y (¬ y = x → ¬ (Wy ∧ Syt)) ∧ Kx)
or:
(∃x: (Wx ∧ Sxt) ∧ (∀y: Wy ∧ Syt) x = y) Kx
∃x ((Wx ∧ Sxt) ∧ ∀y ((Wy ∧ Syt) → x = y) ∧ Kx)

K: [ _ was well-known]; S: [ _ spoke to _ ]; W: [ _ is a winner]; t: Tom

   
with the description operator:

The winner who spoke to Tom was well-known

The winner who spoke to Tom was well-known

K the winner who spoke to Tom

K(Ix (x is a winner who spoke to Tom))

K(Ix (x is a winner ∧ x spoke to Tom))

K(Ix (Wx ∧ Sxt))

  c.
using Russell’s analysis:

The winner, who spoke to Tom, was well-known.

The winner is such that (he or she, who spoke to Tom, was well-known).

(∃x: x is a winneronly x is a winner) x, who spoke to Tom, was well-known)

(∃x: x is a winner ∧ (∀y: ¬ y = x) ¬ y is a winner) (x spoke to Tom ∧ x was well-known)

(∃x: Wx ∧ (∀y: ¬ y = x) ¬ Wy) (Sxt ∧ Kx)
∃x (Wx ∧ ∀y (¬ y = x → ¬ Wy) ∧ (Sxt ∧ Kx))
or:
(∃x: Wx ∧ (∀y: Wy) x = y) (Sxt ∧ Kx)
∃x (Wx ∧ ∀y (Wy → x = y) ∧ (Sxt ∧ Kx))

K: [ _ was well-known]; S: [ _ spoke to _ ]; W: [ _ is a winner]; t: Tom

with the description operator:

The winner, who spoke to Tom, was well-known.

The winner spoke to Tomthe winner was well-known

S the winner Tom ∧ K the winner

S(Ix x is a winner)t ∧ K(Ix x is a winner)

S(Ix Wx)t ∧ K(Ix Wx)

  d.
using Russell’s analysis:

Every number greater than one is greater than its positive square root

(∀x: x is a number greater than one) x is greater than its positive square root

(∀x: x is a number ∧ x is greater than one) x is greater than the positive square root of x

(∀x: Nx ∧ Gxo) the positive square root of x is such that (x is greater than it)

(∀x: Nx ∧ Gxo) (∃y: y is a positive square root of x ∧ only y is a positive square root of x) x is greater than y

(∀x: Nx ∧ Gxo) (∃y: (y is positive ∧ y is a square root of x) ∧ (∀z: ¬ z = y) ¬ (z is positive ∧ z is a square root of x)) Gxy

(∀x: Nx ∧ Gxo)
(∃y: (Py ∧ Syx) ∧ (∀z: ¬ z = y) ¬ (Pz ∧ Szx)) Gxy

∀x ( (Nx ∧ Gxo)
→ ∃y ((Py ∧ Syx) ∧ ∀z (¬ z = y → ¬ (Pz ∧ Szx)) ∧ Gxy) )

or:

(∀x: Nx ∧ Gxo)
(∃y: (Py ∧ Syx) ∧ (∀z: Pz ∧ Szx) y = z) Gxy

∀x ( (Nx ∧ Gxo)
→ ∃y ((Py ∧ Syx) ∧ ∀z ((Pz ∧ Szx) → y = z) ∧ Gxy) )

G: [ _ is greater than y]; N: [ _ is a number]; P: [ _ is positive]; S: [ _ is a square root of _ ]

   
with the description operator:

Every number greater than one is greater than its positive square root

(∀x: x is a number ∧ x is greater than one) x is greater than the positive square root of x

(∀x: Nx ∧ Gxo) G x the positive square root of x

(∀x: Nx ∧ Gxo) Gx(Iy y is a positive square root of x)

(∀x: Nx ∧ Gxo) Gx(Iy (y is a positive ∧ y is a square root of x))

(∀x: Nx ∧ Gxo) Gx(Iy (Py ∧ Syx))
∀x ( (Nx ∧ Gxo) → Gx(Iy (Py ∧ Syx)) )

2. a.

(∃x: x owns Spot ∧ (∀y: ¬ y = x) ¬ y owns Spot) x called

(∃x: x owns Spotonly x owns Spot) x called

The owner of Spot is such that (it called)

Spot’s owner called

  b.

John found (Ix (x is a photographer ∧ x enlarged (Iy y is a picture of John)))

John found (Ix (x is a photographer ∧ x enlarged the picture of John))

John found (Ix (x is a photographer who enlarged the picture of John))

John found the photographer who enlarged the picture of him

Glen Helman 20 Jul 2012