Phi 270 F04 test 4 in pdf format
Analyze the sentences below in as much detail as possible, providing a key to the non-logical vocabulary you use. Restate 2 using an unrestricted quantifier.
1. Sam checked every lock
[answer]
2. No one who was in the office answered the call
[Remember to restate your answer in 2 using an unrestricted quantifier.]
[answer]
3. Ralph got the joke if anyone did
[answer]
4. Only bestsellers were on every list
[answer]
Use derivations to show that the following arguments are valid. You may use any rules.
5.
∀x Fx
∀x ¬ Gx
∀x (Fx ∧ ¬ Gx)
[answer]
6.
(∀x: Rxa) ∀y Txy
∀x (∀y: Rya) Tyx
[answer]
Use a derivation to show that the following argument is not valid and present a counterexample by describing a structure that divides an open gap. (You may describe the structure either by depicting it in a diagram, as answers in the text usually do, or by giving tables.)
7.
∀x Rax
(∀x: Rxa) Rxx
[answer]

Phi 270 F04 test 4 answers
1.

Sam checked every lock

Every lock is such that (Sam checked it)

(∀x: x is a lock) Sam checked x

(∀x: Lx) Csx
[C: λxy (x checked y); L: λx (x is a lock); s: Sam]
2.

No one who was in the office answered the call

No one who was in the office is such that (he or she answered the call)

(∀x: x is a person who was in the office) ¬ x answered the call

(∀x: x is a personx was in the office) ¬ Axc

(∀x: Px ∧ Nxo) ¬ Axc
∀x ((Px ∧ Nxo) → ¬ Axc)
[A: λxy (x answered y); P: λx (x is a person); N: λxy (x was in y); c: the call; o: the office]
3.

Ralph got the joke if anyone did

Everyone is such that (Ralph got the joke if he or she did)

(∀x: x is a person) Ralph got the joke if x did

(∀x: Px) (Ralph got the jokex got the joke)

(∀x: Px) (Grj ← Gxj)
(∀x: Px) (Gxj → Grj)
[P: λx (x is a person); G: λxy (x got y); j: the joke]
4.

Only bestsellers were on every list

Only bestsellers are such that (they were on every list)

(∀x: ¬ x is a bestseller) ¬ x was on every list

(∀x: ¬ Bx) ¬ every list is such that (x was on it)

(∀x: ¬ Bx) ¬ (∀y: y is a list) x was on y

(∀x: ¬ Bx) ¬ (∀y: Ly) Nxy
[B: λx (x is a bestseller); L: λx (x is a list); N: λxy (x was on y)]
5.
│∀x Fx a: 3
│∀x ¬ Gx a: 5
├─
│ⓐ
3 UI │││Fa (4)
│││●
││├─
4 QED │││Fa 2
││
5 UI │││¬ Ga (6)
│││●
││├─
6 QED │││¬ Ga 2
│├─
2 Cnj ││Fa ∧ ¬ Ga 1
├─
1 UG │∀x (Fx ∧ ¬ Gx)
6.
│(∀x: Rxa) ∀y Txy c:3
├─
│ⓑ
││ⓒ
│││Rca (3)
││├─
3 SB │││∀y Tcy b: 4
4 UI │││Tcb (5)
│││●
││├─
5 QED │││Tcb 2
│├─
2 RUG ││(∀y: Rya) Tyb 1
├─
1 UG │∀x (∀y: Rya) Tyx
7.
│∀x Rax a:3, b:4
├─
│ⓑ
││Rba
│├─
│││¬ Rbb
││├─
3 UI │││Raa
4 UI │││Rab
│││○ Rba, ¬Rbb, Raa, Rab ⇏⊥
││├─
│││⊥ 2
│├─
2 IP ││Rbb 1
├─
1 RUG │(∀x: Rxa) Rxx

Counterexample presented by a diagram

Counterexample presented by tables

range: 1, 2  
ab
12
 
R 1 2 
1 T T 
2 T F